| chemistry question that i need help with thanks?
The reaction is:3NaOH + H3PO4 ----> Na3PO4 + 3H2OM = mol / Lmol = M x Lmol H3PO4 = 5.00 x 10^-3 mol/L x 0.1=0150 L = 7.5 x 10^-5 mol H3PO43 mol NaOH react with 1 mol H3PO47.5 x 10^-5 mol H3PO4 x (3 mol NaOH / 1 mol H3PO4) = 2.25 x 10^-4 mol NaOHM = mol / LL NaOH = mol / M = 2.25 x 10^-4 mol / 0.0100 mol/L = 0.0225 L = 22.5 mL
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