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College Chemistry 2 question?
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03-02-2008, 01:01 PM
RONALD E B
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1.98 molal Fe(NO3)3 = 1.98 moles Fe(NO3)3 plus 1000 g H2O
1000 g H2O = 55.50 moles H2O
1.98 moles / (55.50 + 1.98) = 0.0344
mole fraction of F3(NO3)3 = 0.0344
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