| 1
93.0 x 500 = 221 V2
V2 =210.4 mL ( at constant temperature)
2.
T1 = 99 + 273 = 372 K
0.67 / 372 = 1.39 / T2
T2 = 771.8 K
771.8 - 273 = 498.8°C ( at constant volume)
3.
p = 30700 Pa / 101325 =0.303 atm
n = pV / RT = 0.303 x 0.659 / 0.0821 x 303 = 0.00803
original pressure = 0.00803 x 0.0821 x 294 / 0.779 L =0.249 atm
4.
T = pV /n R = 0.980 x 1.20 / 0.0538 x 0.0821 =266 K
5.
C3H8 +5 O2 >> 3CO2 + 4 H2O
the ratio is 1 : 5
liters of O2 = 30.4 x 5 = 152 L |