In the following reaction is run by combining 95.0g of NaOH, 141g of Cl2, and 125g of Ca(OH)2.
2NaOH + Ca(OH)2 + 2Cl2-------> Ca(OCl)2 + 2NaCl +2H20
Determine:
(a) The Limiting Reagent.
(b) How mcuh is left over of EACH reagent.
(c) The amount of Ca(OCl)2 that can be made.
(d) The % yield if the amount of water collected was 31.5g.
Thanks so much for your time and consideration it is GREATLY appreciated!!!
