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| CaC2 + 2 H2O --> C2H2 + Ca(OH)2 a) mole of CaC2 = 479 / 64 = 7.484 mol mole of H2O needed = 2/1 * mole of CaC2 = 14.968 mol [ratio of coefficients = ratio of moles] mass of H2O needed = 14.968 * 18 = 269.424 g b) mole of C2H2 = 23.6 / 26 = 0.908 mol mole of CaC2 needed = 1/1 * mole of C2H2 = 0.908 mol mass of CaC2 needed = 0.908 * 64 = 58.112 g c) mole of Ca(OH)2 = 51.3 / 74 = 0.693 mol mole of H2O = 2/1 * mole of Ca(OH)2 = 1.386 mol mass of H2O = 1.386 * 18 = 24.948 g |
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| hurry please chemistry!!? Calcium carbide, CaC2, reacts with water to form acetylene. CaC2(s) + 2 H2O(l) C2H2(g) + Ca(OH)2(s) (a) How many grams of water are needed to react with 479 g of calcium carbide? (b) How many grams of CaC2 could make 23.6 g C2H2? (c) If 51.3 g Ca(OH)2 are formed, how many grams of water reacted? |
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