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04-04-2008, 08:41 AM
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| chemistry helpp??? What is the freezing point depression of an aqueous solution of 10.0 g of glucose (C6H13O6) (glucose) in 50.0 g H20 (water)? can you also help me with this one to : What mass of NaCl would have to be dissolved in 1.000 kg of water to raise the boiling point by 2.00 Celsius?      |
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04-04-2008, 08:45 AM
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| Moles glucose ( non electrolyte) = 10.0 g / 180 g/mol = 0.0556 molality = 0.0556 / 0.0500 Kg = 1.11 delta T = kf x m = 1.86 x 1.11 = 2.06 °C NaCl is an electrolyte for which i = 2 2.0 °C = m x 0.512 x 2 m = 1.95 = moles / 1.00 Kg moles = 1.95 mass = 1.95 mol x 58.44 g/mol = 114.0 g |
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