Chemistry Problem Please Help! :]]?

[Adri*]

How many grams of CuSO4*5H2O are needed to 0.1L of a 0.10 M solution?

I'm not sure how to approach the CuSO4*5H2O part...

Please Help :]]
10 points to best answer.
you do not have to complete the problem just explain the significance of the CuSO4*5H2O and how i should solve it. Thanks

[rubidium.chloride]

Well, the first thing you ought to do is to multiply 0.1 L by 0.10 M. That way, you'll find out how many moles CuSO4*5H2O were there.

0.1 L * 0.10 mol CuSO4*5H2O / 1 L

Then, multiply the thing by its molar mass.

0.1 L * 0.10 mol CuSO4*5H2O / 1 L * 249.68 g CuSO4*5H2O / 1 mol CuSO4*5H2O = 2.5 g