Chemistry question?

Dr.A · #1 (**permalink**) 02-29-2008, 03:04 PM

Moles Na2S2O3 = 0.03520 L x 0.150 M = 0.00528
the ratio between I2 and Na2S2O3 is 1 : 2
moles I2 = 0.00528 / 2 = 0.00264
V = moles / M = 0.00264 / 0.2554 = 0.0103 L = 10.3 mL

steve b · #2 (**permalink**) 02-29-2008, 03:04 PM

Iodine I2 reacts with aqeous soldium thiosulfate NA2S2O3 according to the following balanced equation:
I2(aq) +2NA2S2O3(2-)(aq) ---> S4O6(2-)(aq) +4NA+(aq)

What volume of 0.2554 M I2 solution would react completely with 35.20mL of 0.150 M NA2S2O3 solution?

I've tried everything and I can't get the right answer

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