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| Dr. A!!!!!!!!! MOLARITY,MOLALITY: chemistry?
i really need help from anyone who knows how. i know its waste of your time but it would help me a whole lot and make a huge difference. i dont know HOW to do these problems. please please please help. dont give me the answer but show me how to do it. im bad at chem. so if you could make it easy it would help alot haha What would be the molality of 3.40 L of a 0.490 M solution? What is the molarity of each resulting solution when the following mixtures are prepared? (a) 590.2 mL H2O is added to 20.0 mL 6.07 M HNO3 (b) 32.0 mL 1.75 M HCl is added to 80.0 mL 0.335 M HCl Calculate the molality of the following solutions. (a) 22.9 g NaCl in 103.7 g H2O (b) 28.9 g CaCl2 in 744.1 g H2O (c) 2.79 g NaOH in 0.778 L H2O How many grams of solute are contained in the following solutions? (a) 71.5 mL 0.0199 M KOH (b) 182 mL 1.28 M K2SO4 (c) 698.0 mL 0.242 M NH4OH helppppp please |
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(a) Moles HNO3 = 0.0200 L x 6.07 =0.121 total volume = 610.2 mL = 0.6102 L M = 0.121/ 0.6102 =0.198 (b) moles HCl = 0.032 x 1.75 =0.056 Moles HCl = 0.080 x 0.335 = 0.0268 total moles = 0.0828 total volume = 112 mL = 0.112 L M = 0.0828 / 0.112 =0.739 (a) Moles NaCl = 22.9 /58.453 =0.392 m = 0.392 / 0.1037 Kg =3.78 (b) moles CaCl2 = 28.9 / 110.9 = 0.261 m = 0.261 / 0.7441 Kg =0.350 (c) Moles NaOH = 2.79 / 40 g/mol =0.0698 m = 0.0698 / 0.778 = 0.0897 ( since density of water is 1 g/mL) (a) moles = 0.0715 x 0.0199 =0.00142 mass = 0.00142 x 56 g/mol =0.0797 g (b)moles = 0.182 x 1.28 =0.233 mass = 0.233 x 174.2 =40.6 g (c) moles = 0.698 x 0.242 =0.169 mass = 0.169 x 35 = 5.92 I hope this help you |
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