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03-18-2008, 05:51 PM
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| CHEMISTRY - can YOU do this problem? Calculate delta Hrxn for the reaction below. 2 NOCl(g) --> N2(g) + O2(g) + Cl2(g) You are given the following set of reactions. 1/2 N2(g) + 1/2 O2(g) --> NO(g) DELTA H = 90.3 kJ NO(g) + 1/2 Cl2(g) --> NOCl(g) DELTA H = -38.6 kJ      |
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