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03-11-2008, 06:26 PM
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| Helping a friend with calc, but stuck on this one. Will pick best ans.?
How do I do the integral of (x+1) / sqrt(9-x) dx, using integration by parts?? Help, please!!
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03-11-2008, 06:26 PM
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(x+1) / sqrt(9 - x) dx u = x + 1 du = dx dv = 1 / sqrt(9 - x) dx v = -2sqrt(9 - x) Int [(x+1) / sqrt(9 - x) dx] = (x + 1)(-2sqrt(9 - x)) - Int [-2sqrt(9 - x)]dx =(x + 1)(-2sqrt(9 - x)) - (4/3)(9 - x)^(3/2) |
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