Can anyone please help me with my chemistry homework?

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The question goes like this.

An excess of calcium nitrate solution was added to 50ml of a sodium fluoride solution. The white precipitate of calucium fluoride that was obtained was filtered off and dried. The mass of this calcium fluoride precipitate was 2.93g. The equation for the reaction is; Ca(NO3)2(aq) + 2NaF(aq) ----> CaF2(s) + 2NaNO3(aq). Determine the concentration of the sodium fluoride solution.

I would appreciate if someone got to me back fast because it is due tomorrow, and it is the last question i have to do. I do not want the answer right off the bat, i would actually like to know the process of getting it. Thank you.