Help with chem, rates and laws?

[Ryan N]

The rate constant = 5 x 10 ^5
Forward Rate = 300 s ^-1
Reverse Rate = 4.8 x 10 ^-3 s^-1

A catalyst increases the forward rate by 1 x 10 ^5 s^-1
What is the new value of the reverse rate after adding the catalyst?

I know that a catalyst will change the forward and reverse rate constants by exactly the same factor.