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1. The principle is that you treat each letter like a piece of fruit. Suppose you have apples (a) and bananas (b). 4a + 2a means you have 4 apples and someone gives you another 2 apples. How many apples do you have? Answer: 6a. 5b - 3b means you have 5 bananas and you give 3 to someone else. How many bananas do you now have? Answer: 2b. 4a + 5b + 2a - 3b means you have 4 apples and 5 bananas and you receive 2 apples and you lose 3 bananas. What do you end up with? Answer: 6a + 2b. A tricky case is something like 3a - 10a. That means something like you have 3 apples but you owe someone 10 apples. If you give them what you have, how many do you still owe? Answer: 3 - 10 = -7 (you owe 7), so 3a - 10a = -7a. 2. Parentheses are like bags. 3(a + 2b) means something like you have 3 bags, each bag has 1 apple and 2 bananas. How many do you have in total? Obviously 3 apples and 6 bananas. How do you do it? You multiply the 3 times each of the terms in the brackets, so 3(a + 2b) = 3 times a + 3 times 2b = 3a + 6b. |
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| Maths Homework Help!! (More homework)?
I have no idea how do these sums. can someone explain it to me. 1. Simplify these expressions. a)3z + 2y - z b) 5a - 3a + 6a c) 4w + 2v - 4v +2w d) 5c - 3d - 2d e) 3 + t + 3f - 2g + 8 f) f - 7 + 3f - 2g + 8 g) 3s + 2r - 7 + 3r - 7s + 4 h) 3 - 2h - 3j + h - 4 2. Expand and simplify these expressions. a) p + 2(p + q) b) 2(r + 2s) + 3s c) 5t + 2(u + t) - 3u d) 3(v + 2w - x)- 4x + w .ect!! 3...... 4. Build these expressions. a) e times f, add 4, times by 8 b) h plus j, square answer, subtract k c) m times 2, subtract n, times by p, add q SOMEONE HELP!! I DON't GET IT!! |
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You may only add and subtract the "like" terms. These are the ones that have exactly the same letters (variables) or lack of variables (constants). To combine the like terms, simply add or subtract the numbers in front of the letters as the plus or minus symbols indicate (i.e., 3x + 2x = 5x, -3y + 2y - 5y = -6y, 5n - 3 + 6 - n = 4n - 3). In the last example, not that the last n had no number shown in front of it. This is only done when the number is 1. If you write the 1 in, it often makes it easier to remember. Notice also the numbers -3 and 6 were like constant terms and were added like all positive and negative numbers. In your part 2 you will do the same thing after you get rid of the parentheses by distributing the number outside. This means you multiply each term inside the parenthesis by what is directly in front (or behind) it. For instance, 3(x + 2) = 3x + 6 as both the x and 2 are multiplied by the 3. In 5n + 4(m + 3n) you first multiply by the 4 and then add any like terms: 5n + 4(m + 3n) = 5n + 4m + 12n = 17n + 4m. For part 4, work your way out and use parentheses as needed. e times f is ef. To add 4 gives you ef + 4. Now use parentheses. (ef+4). Times it by 8 is to multiply by 8 which is written (ef+4)8 or 8(ef+4). |
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1. Simplify these expressions. a) 3z + 2y - z = 3z - z + 2y = 2z + 2y b) 5a - 3a + 6a = 2a + 6a = 8a c) 4w + 2v - 4v +2w = 4w + 2w + 2v - 4v = 6w - 2v d) 5c - 3d - 2d = 5c - 5d e) 3 + t + 3f - 2g + 8 = t + 3f - 2g + 8 + 3 = t + 3f - 2g + 11 f) f - 7 + 3f - 2g + 8 = f + 3f - 2g - 7 + 8 = 4f - 2g + 1 g) 3s + 2r - 7 + 3r - 7s + 4 = 3s - 7s + 2r - 7 + 4 = - 4s + 2r - 3 h) 3 - 2h - 3j + h - 4 = -2h + h - 3j + 3 - 4 = -1h - 3j -1 = -h - 3j - 1 2. Expand and simplify these expressions. a) p + 2(p + q) = p + 2*p + 2*q = p + 2p + 2q = 3p + 2q b) 2(r + 2s) + 3s = 2*r + 2*2s + 3s = 2r + 4s + 3s = 2r + 7s c) 5t + 2(u + t) - 3u = 5t + 2*u + 2*t - 3u = 5t + 2t + 2u - 3u = 7t - u d) 3(v + 2w - x)- 4x + w = 3*v + 3*2w - 3*x - 4x + w = 3v + 6w - 3x - 4x + w = 3v + 6w + w - 7x = 3v + 7w - 7x .ect!! 3...... 4. Build these expressions. a) e times f, add 4, times by 8 = e*f + 4*8 = ef + 32 b) h plus j, square answer, subtract k = (h + j)^2 - k c) m times 2, subtract n, times by p, add q = m*2 - n * p + q = 2m - np + q .....Where is your question number 3 if you know how to solve it by your self than you don't have any problem now |
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