math problem? show all work please?

[sam B]

a rectangular patio measuring 6 meters by 8 meters is to be increased in size to an area measuring 150 square meters. if both the width and the length are to be increased by the same amount, what is the # of meters, to the nearest tenth that the dimensions will be increased?

[John V]

(6+x)(8+x)=150, or x^2 +14x - 102 = 0. Use quadratic formula to solve for x: [-14 +/-sqrt(196 + 408) ]/2 ==> x = 5.3.
Both dimensions increased by 5.3m

[Jun Agruda]

(x + 6)(x + 8) = 150
x = 5.3

Answer: Dimensions must be increased by 5.3 meters.

Proof:
= (5.3 + 6)(5.3 + 8)
= 11.3 * 13.3
= 150.29