Math riddle, want to try??

[No_where_In_the_UK]

How many distinct arrangements (in a row) can be made with the letters in the word:

BOXING

and

SPINELESS


I have no idea what the answers are.

[hanep]

In boxing: all 6 letters are distinct. Thus there are 6!.

In spineless: 9 letters but there are 3 s's, and 2 3's
Thus, there are 9! / (3! 2!)

[J B]

For boxing all the letters are different

the answer is 6! = 6 *5*4*3*2*1

for spineless you divide out duplicate letters
9!/(3!2!)