One simple math equation...?

[super_me543]

[(2b + 3)/b^2] + [1/6b] = [(b + 6)/6b^2]

another way to put the problem (sorta...) is:

(2b+3) + (1) = (b+6)
------- + --- = -----
(b^2) + (6b) = (6b^2)

It'd pry be best to go off of the first one...
Its all one problem, like: 2b+3 over b^2 or 2b+3/b^2 etc.

I appreciate the help and an explaination would be great! :]]