Physics help please please?

[Michael M]

What is the momentum of a proton with kinetic energy of 752 MeV. Note, the rest mass of the proton is 938.3 MeV/c2.

[Akshu]

Momentum p = mv
m =(938.3*10^6*1.6*10^-19)J/(3*10^8)^2
m=166.8088*10^-29 Kg
K.E = 752 * 10^6 * 1.6 * 10^-19
K.E = 1203.2 * 10^-13J

K.E = (1/2)m v^2
(1/2) m v^2 = 1203.2*10^-13
mv^2 = 1203.2*2*10^-13
Multiply the above eqn throughout by m
m^2v^2 = 1203.2*2*10^-13 * m
(mv)^2 = 1203.2*2*10^-13 * 166.8088*10^-29
=401408.69632 * 10^-42
mv = p = 633.5682 *10^-21 kgm/s

Hope my calculations are righte