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04-08-2008, 02:59 PM
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| physics+momentum+please help?
A 4.00 kg ball strikes a wall with a velocity of 6.0 m/s to the left. The ball bounces off with a velocity of 4.0 m/s to the right. If the ball is in contact with the wall for 0.25 s, what is the constant force exerted on the ball by the wall? N to the right      |
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04-08-2008, 02:59 PM
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Well before impact the ball has -6*4 = -24 kgm/s momentum leftward (negative). After the collision it has 4*4 =16 kgm/s momentum rightward (posi.tive) Difference is 40 kgm/s. Just divide 40kgm/s by 0.25 sec to get the constant force (=160 kgm/s)
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