Circular Motion Physics Problem...?

[Panda]

If I'm standing on a revolving disc, how does my distance away from the center correlate to my likelihood of flying off? Say I stand 5 feet, 10 feet, and 15 feet away from the center. I'm thinking that I would be more likely to fly off if I'm 15 feet rather than 5 feet away, but I'm not sure how to explain it. Is it because I would have a greater velocity or a greater frictional force would be required?

[Andrew A]

no you would be more likely to fly off at 5 feet. because when you reduce the radius the velocity increases.

in the equation for rotational velocity radius is the denominator. so there for when you make R smaller the fraction in the equation becomes a larger number.

[Kshaw5]

well sure, first think of it at both extremes , which are you more likely to fall off, directly in the middle, or on the edge. It should carry that the further you are away from the center, the greater the forces pushing you off the disc are.

Strictly speaking we're talking about linear velocity, the disc as a whole is spinning the same revolutions per minute but as you step further from center the circuference of circular path being traveled goes from zero to however far you are away, pi r squared...