Physics: two rods problem?

[Nobodycanstopmeintheverse4343]

Two rods, one of Al and the other of Cu are joined end to end. The cross sectional area of each is 5.0 x 10^-4 m², and the length of each is 0.04 m. The free end of the Al rod is kept at 300°C, with the free end of the Cu rod at 25°C. Find the amount of heat transferred in an hour through the 2 rods. (Answer is in Joules.)k(Cu) = 390 J/s-m-°C, k(Al) = 240 J/s-m-°CI think you use the (energy transfered) = k (A) ((Th - Tc)/L), with k being the thermal conductivity, A is area, Th and Tc is the temperature ends, and L is the length of the rod. This equation will give you (energy transfered), in which you can substitute it into another equation: (energy transfered) = Q/(change in time). Change in time would be 3600 seconds since there's 3600 seconds in an hour. Q is our ultimate answer. But how would you go about using the first equation with two rods?The answer is supposed to be around 1.84e6 J, but I don't know how to get there....

[HLLVB]

Q = A(delta T) / (Sum of L/ k) <---- and all multiplied by 3600 to get answer.Q = (5e-4)(300-25) / ((0.04m/390) + (0.04m/240)) = 510.7510.7 * 3600 seconds = 1838571, or 1.84e6 Joules