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05-15-2008, 11:37 PM
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| help physics question relating simple harmonic motion? a particle rests on a horizontal platform which is moving vertically in s.h.m of amplitude 10cm. above a certain frequency, the force between the particle and the platform vanishes at some point in the motion. find the value of this frequency.thanx      |
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05-16-2008, 12:06 AM
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| help physics question relating simple harmonic motion? acceleration of any shm can be described as = -a w^2 sin(wt)where a is amplitudew is the angular frequencyfor force between particle and platform to vanish at any point. g = a w^2 sin(wt)The minimum frequency at which this happens will be when sin(wt)=1g=a w^2so w = √(g/a) = √(9.8/.1) = 9.9 |
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