please help solve this physics question 4 me i do not understand?

[vivian l]

A block of mass 0.245 kg is placed on top of a light vertical spring of force constant 5160 N/m and pushed downward so that the spring is compressed 0.100 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise?

[anil bakshi]

B ************** max height (v=0)
+h

O ================== origin (unstretched spring top level)
x = - 0.1 m
A ------------------------- compressed spring (top) u=0
conservation of energy>
Total energy (at A) = Total energy (at B)
KE + elastic PE + Mech. PE = constant
KE(=0, rest)+0.5 k (- x)^2+mg (-x) = KE(=0, stops)+mg (+h)
0.5 k x^2 - mgx = mgh
h = (k /2mg) x^2 - x
distance from point of release =BA= h+x
BA = (k /2mg) x^2
BA = (5160 /2*0.245*9.8) 0.10*0.10
BA = 10.75 meter